
CBSE Class 10 Constructions (Deleted Chapter 11) 2025 Syllabus
Here is the latest 2025 syllabus update for CBSE Class 10 Maths, Chapter 11, “Constructions.” This entire chapter has been DELETED from the rationalized NCERT syllabus and will not be in the 2025 board exams. This guide explains why this topic was removed, while also providing clear notes and Q&A on its core concepts—like dividing a line segment and constructing tangents—and how they still apply to the “Triangles” and “Circles” chapters.
CBSE Class 10 Maths: Chapter 11 “Constructions”
A guide to the core concepts, Q&A, and syllabus status for 2025.
Syllabus Status: Chapter Deleted
CBSE has removed the entire “Constructions” chapter (formerly Chapter 11) from the Class 10 Mathematics syllabus for the 2024-25 academic session. This topic will not be assessed in the board examinations.
If it’s deleted, why is this page here?
That is a fair question. While you no longer need to practice drawing with a compass, the *principles* behind these constructions are still present in your syllabus.
- The logic for dividing a line segment is based on the **Basic Proportionality Theorem (BPT)** from the “Triangles” chapter.
- The logic for drawing tangents is based on theorems from the **”Circles” chapter**.
Understanding the “why” behind these old constructions can strengthen your grasp of the “Triangles” and “Circles” chapters. This guide is here to explain that logic.
Drawing: Division of a Line Segment (Ratio 5:8)
This drawing shows the method. A ray AX is drawn at an acute angle to line AB. It is marked with 13 (5 + 8) equal points. The last point (A13) is joined to B. A line parallel to A13-B is drawn from A5 to find point C.
Drawing: Tangents from an External Point
This drawing shows the method. To draw tangents from P, first find the midpoint M of the line OP (O is the center). A new circle is drawn with center M and radius MO. The points where this new circle hits the original circle (Q and R) are the points of tangency.
Drawing: Similar Triangle (Scale Factor 3/4)
This drawing shows the method for a scale factor less than 1. A ray BX is drawn. The larger number (4) is used to mark 4 points. The *denominator* point (B4) joins to C. The *numerator* point (B3) is used to draw a parallel line B3-C’, creating the new smaller triangle A’BC’.
Questions & Answers
Q: What is the first step to divide a 10cm line segment in the ratio 3:2?
Hint: You need to find the total number of parts to mark on the ray.
1. Draw the 10cm line segment, let’s call it AB.
2. Draw a ray, AX, making an acute angle with AB.
3. Since the ratio is 3:2, you will mark a total of 3 + 2 = 5 equal points on the ray AX (A1, A2, A3, A4, A5).
Q: In the 3:2 ratio division (A5), which point do you join to B? And which point do you use for the parallel line?
Hint: The *last* point always joins the end of the line. The *first number* in the ratio is used for the new point.
1. You join the last point, A5, to the end of the line, B. This forms the line A5-B.
2. You use the first number of the ratio (3), so you draw a line from point A3 parallel to A5-B.
3. This parallel line from A3 will intersect AB at the point C, which divides the line in the ratio 3:2.
Q: What is the mathematical principle that allows the tangent construction to work?
Hint: It involves a 90-degree angle and a property of circles.
The construction works because of two theorems:
1. **”The angle in a semicircle is a right angle (90 degrees).”** When you draw the new circle with OP as the diameter, the point of tangency (Q) on that circle forms a 90-degree angle (angle OQP = 90).
2. **”A tangent is perpendicular to the radius at the point of tangency.”** Because we created a 90-degree angle at OQP, we have proven that the line PQ is perpendicular to the radius OQ. This makes PQ a tangent.
Q: To construct a similar triangle with a scale factor of 7/4, how many points do you draw on the ray?
Hint: You always mark the *larger* of the two numbers from the scale factor.
You mark 7 points (B1 to B7) on the ray, as 7 is the larger number in the scale factor 7/4.
Q: For the 7/4 scale factor, which point joins the base? Which point is used for the parallel line?
Hint: Remember the rule: “Denominator Joins, Numerator Parallels”.
The scale factor is 7/4.
1. **Denominator (4) Joins:** You join point B4 to the base vertex C.
2. **Numerator (7) Parallels:** You draw a line from point B7 that is parallel to B4-C. This will meet the extended base at C’.




